Prove that the area of a rhombus is equal to half of the product of th

1.	Prove that the area of a rhombus is equal to half of the product of the diagonals.E SAM
Answer» GIVEN ABCD is a rhombus the diagonal AC and BD cut at POINT O Then ∠AOD=∠AOB=∠COD=∠BOC=90 0 The area of rhombus ABCD divided diagonal in FOUR parts So area of rhombus ABCD =area of triangle AOD+area of triangle AOB+area of triangle BOC+area of triangle COD = 1/2×AO×OD+1/2×AO×OB+ 1/2×BO×OC+ 1/2OD×OC =1/2AO(OD+OB)+1/2OC(BO+OD) =1/2×AO×BD+1/2×OC×BD =1/2BD(AO+OC)=1/2×BD×AC So area of rhombus is equal to half of the product of diagonals *Hope* it helps you *please* *mark* me as brainliest *THANK* *you*!

Prove that the area of a rhombus is equal to half of the product of the diagonals.E SAM

Answer»

GIVEN ABCD is a rhombus the diagonal AC and BD cut at POINT O

Then ∠AOD=∠AOB=∠COD=∠BOC=90

The area of rhombus ABCD divided diagonal in FOUR parts

So area of rhombus ABCD =area of triangle AOD+area of triangle AOB+area of triangle BOC+area of triangle COD

= 1/2×AO×OD+1/2×AO×OB+ 1/2×BO×OC+ 1/2*OD×OC

=1/2*AO(OD+OB)+1/2*OC(BO+OD)

=1/2×AO×BD+1/2×OC×BD

=1/2*BD(AO+OC)=1/2×BD×AC

So area of rhombus is equal to half of the product of diagonals