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Prove that the current flowing through an ideal inductor connected across a.c. source lags behind the voltage in phase by pi/2. |
| Answer» SOLUTION :Show as in Short Answer Question Number 2 above that for V = V, sin ot, the current `I = I_(m) sin (omegat - pi/2)` This proves that the current flowing through an ideal INDUCTOR LAGS behind an a.c. VOLTAGE in phase by `pi/2`. | |