Prove that the points (1,4), (3, -2) and (-3, 16) are collinear.

1.	Prove that the points (1,4), (3, -2) and (-3, 16) are collinear.
Answer» $\huge\underline\mathbb{\red S\pink{O}\purple{L} \blue{UT} \orange{I}\green{ON :}}$ ★ Given that, A(1, 4) B(3, -2) C(-3, 16) ★ Collinear : The POINTS which lie on the same line is known as " Collinear points " . ★ LET, x1 = 1 ; y1 = 4 x2 = 3 ; y2 = - 2 x3 = - 3 ; y3 = 16 By using Area of triangle formula $\frac{1}{2} \| x_{1}(y _{2} - y _{3}) + x _{2}(y _{3} - y _{2}) + x_{3}(y _{1} - y _{2}) \|$ Substitute the VALUES. $⟹ \frac{1}{2} \| 1( - 2 - 16) + 3(16 - 4) + ( - 3)(4 - ( - 2)) \|$ $⟹ \frac{1}{2} \| 1( - 18) + 3(12) - 3(6)\|$ $⟹ \frac{1}{2} \| - 18 + 36 - 18\|$ $⟹ \frac{1}{2} \| - 36 + 36\|$ $⟹ \frac{1}{2} \|0\|$ $⟹0$ ∴ Hence, these points are collinear points. Step-by-step explanation: $# PLEASE MARK ME AS BRAINLIEST✌✌✌$

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$\huge\underline\mathbb{\red S\pink{O}\purple{L} \blue{UT} \orange{I}\green{ON :}}$