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Prove that the ponts `A(1,2,3),B(3,4,7),C(-3 -2, -5)` are collinear and find the ratio in which B divides AC. |
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Answer» Clearly, `AB=(3-1)hati+(4-2)hatj+(7-3)hatk` `=2hati+2hatj+4hatk` and `BC=(-3-3)hati+(-2-4)hatj+(-5-7)hatk` `=6hati-6hatj-12hatk` `=-3(2hati+2hatj+4hatk)=-3AB` `becauseBC=-3AB` `therefore` A,B and C are collinear, Now, let C diivide AB in the ratio k:1, then `OC=(kOB+1*OA)/(k+1)` `implies-3hati-2hatj-5hatk=(k(3hati+4hatj+7hatk)+(2hati+2hatj+3hatk))/(k+1)` `implies-3hati-2hatj-5hatk=((3k+1)/(k+1))hati+((4k+2)/(k+1))hatj+((7k+3)/(k+1))hatk` `implies(3k+1)/(k+1)=-3,(4k+2)/(k+1)=-2 and ((7k+3)/(k+1)=-5` From, all relations, we get `k=(-2)/(3)` Hence, C divides AB externally in the ratio 2:3. |
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