prove that"the tangent at any point of a circle is prependicular to th

1.	prove that"the tangent at any point of a circle is prependicular to the radius through the point of contact".
Answer» Answer: Referring to the figure: OA=OC (Radii of circle) Now OB=OC+BC ∴OB>OC (OC being RADIUS and B any point on TANGENT) ⇒OA B is an arbitrary point on the tangent. Thus, OA is shorter than any other LINE segment joining O to any point on tangent. Shortest distance of a point from a given line is the perpendicular distance from that line. Hence, the tangent at any point of circle is perpendicular to the radius.

prove that"the tangent at any point of a circle is prependicular to the radius through the point of contact".

Answer»

Answer:

Referring to the figure:

OA=OC (Radii of circle)

Now OB=OC+BC

∴OB>OC (OC being RADIUS and B any point on TANGENT)

⇒OA

B is an arbitrary point on the tangent.

Thus, OA is shorter than any other LINE segment joining O to any

point on tangent.

Shortest distance of a point from a given line is the perpendicular distance from that line.

Hence, the tangent at any point of circle is perpendicular to the radius.

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prove that"the tangent at any point of a circle is prependicular to the radius through the point of contact".​

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prove that"the tangent at any point of a circle is prependicular to the radius through the point of contact".