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Prove the Boolean identity : (A+B)(A+C) = A+BC |
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Answer» SOLUTION : Proof: Applying the LAW of distribution on LHS of the equation, we GET ` (A+B) (A+C) =A A +AC+BA + BC ` ` =A+AC+AB +BC` ` =A(1+C+B)+BC` ` =A+BC` ` [ :.1+C+B=1]` ` thereforeLHS=RHS ` thegivenidentityisproved . |
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