1.

Prove the identity: sin6 x + cos6 x = 1 – 3 sin2 x cos2 x

Answer»

Let us consider the LHS: sin6 x + cos6 x

(sin2 x)3 + (cos2 x)3

On using the formula, a3 + b3 = (a + b) (a2 + b2 – ab)

(sin2 x + cos2 x) [(sin2 x)2 + (cos2 x)2 – sin2 x cos2 x]

On using the formula, sin2 x + cos2 x = 1 and a2 + b2 = (a + b)2 - 2ab

1 × [(sin2 x + cos2 x)2 – 2sin2 x cos2 x – sin2 x cos2 x

12 – 3sin2 x cos2 x

1 – 3sin2 x cos2 x

= RHS

∴ LHS = RHS

Thus proved.



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