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Prove ZA + ZB = 2 ZCOD The diagonals of a rectangle ABCD intersect at 0. If ZAOB = 30°, find ZCOD and ZOCD |
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Answer» AnswerFrom FIGURE,∠COD=∠AOB (Vertically opposite ANGLES) =>∠COD=30 o In △OCD,∠OCD+∠ODC+∠COD=180 o ∠OCD+∠OCD+∠COD=180 o (Diagonals are equal in RECTANGLE)2∠OCD+30 o =180 o ∠OCD=75 o |
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