InterviewSolution
Saved Bookmarks
| 1. |
प्रस्तुत चित्र में O वृत्त का केंद्र है तथा `angle ABO = 60 ^(@)` तब `angle ACB = `A. `60^(@)`B. `30^(@)`C. `120^(@)`D. `15^(@)` |
|
Answer» Correct Answer - B `because angleABO=60^(@)` `therefore angle OAB=angleABO=60^(@)` `angleAOB=180^(@)-(angle ABO+angleOAB)` `=180^(@)-(60^(@)+60^(@))` `=180^(@)-120^(@)=60^(@)` `angleACB=(1)/(2)angleAOB=(1)/(2)xx60^(@)=30^(@)` |
|