1.

प्रस्तुत चित्र में O वृत्त का केंद्र है तथा `angle ABO = 60 ^(@)` तब `angle ACB = `A. `60^(@)`B. `30^(@)`C. `120^(@)`D. `15^(@)`

Answer» Correct Answer - B
`because angleABO=60^(@)`
`therefore angle OAB=angleABO=60^(@)`
`angleAOB=180^(@)-(angle ABO+angleOAB)`
`=180^(@)-(60^(@)+60^(@))`
`=180^(@)-120^(@)=60^(@)`
`angleACB=(1)/(2)angleAOB=(1)/(2)xx60^(@)=30^(@)`


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