1.

Prussionblue is formedwhen :

Answer»

Ferroussulphatereacts with `FeCI_(3)`
Forric sulphatee REACTSWITH `K_(4)[Fe(CN)_(6)]`
Ferrousammoniumsulphatee REACTS with `FeCI_(3)`
Ammoniumsulphate reacts with `FeCI_(3)`

SOLUTION :`2Fe_(2)(SO_(4))_(3) + 3K_(4)[Fe(CN)_(6)] rarr underset("Prussian blue")(Fe_(4)[Fe(CN)_(6)]_(3))+6K_(2)SO_(4)`


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