1.

Pt|Cl_(2)(P_(1)atm)|HCl(0.1M)|Cl_(2)(P_(2)atm)|Pt, cell reaction will be spontaneous if

Answer»

`p_(1)=p_(2)`
`p_(1)gtp_(2)`
`p_(2)gtp_(1)`
`P_(1)=P_(2)=1atm`

Solution :`E_(cell)=E_(cell)^(0)-(0.591)/(2)log_(10)((P_(Cl_(2)_(anode)))/(P_(Cl_(2)(cathode))))=0-(0.0591)/(2)log_(10)((P_(1))/(P_(2)))`
if `P_(1)ltP_(2),E_(cell)=+ve` (SPONTANEOUS)


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