1.

Pure benzene freezes at 5.3^(@)C. A solution of 0.223 of phenylacetic acid (C_(6)H_(5)CH_(2)COOH) in 4.4 g of benzene (K_(f) = 5.12 Kg mol^(-1)) freezes at 4.47^(@)C. From this observation, one can conclude that

Answer»

Phenylacetic ACID exists as such in benzene
Phenylacetic acid undergoes partial ionization in benzene
Phenylacetic acid undergoes complete ionization in benzene
Phenylacetic acid dimerizes in BENZEN

Solution :`Delta T_(f)=T_(0)-T_(f)=5.3-4.47=0.83`
molality of solvent `m = (0.223)/(136)xx(1000)/(4.4)=0.373`
(Molecular weight of phenylacetic acid = 136)
`K_(f)=5.12`
`Delta T_(f) =i. K_(f)m`
`i=(Delta T_(f))/(K_(f)m)=(0.83)/(5.12xx0.373)=0.45`
i is NEARLY equal to 0.5 it MEANS phenylacetic acid undergoes dimerization in benzene.


Discussion

No Comment Found

Related InterviewSolutions