1.

Pure sulphur was burnt. the gaseous products are SO_(2)=60% (mol), SO_(3)=20% (mol) and O_(2)=20% (mol). If initially 50 moles of sulphur was taken then how many moles of O_(2) should be taken.

Answer»

110
68.75
55
50

Solution :Assume that MOLE of PRODUCT mixture =x mole
`n_(a)=50=xxx0.6+x xx0.2-0.8x`
`x=(50)/(0.8)=(500)/(8)=62.5`
`n_(o_(2))` remain=62.5xx0.2-12.5
`n_(o)=2xxn_(SO_(2))+3xxn_(SO_(3))=2xx x xx0.6+3xx x xx0.2`
`n_(o)=1.2x+0.6x=1.8x=1.8xx62.5`
`n_(o_(2))=(1.8xx65)/(2)=0.9xx65=56.25`
`n_(o_(2))` TOTAL require `=56.25+12.5=68.75`


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