Pure water can be supercooled down to -10^(@)C. If a small ice crystal is thrown into, it immediately freezes. What fraction of water will freeze? The system is adiabatically isolated.

Pure water can be supercooled down to -10^(@)C. If a small ice crystal

1.	Pure water can be supercooled down to -10^(@)C. If a small ice crystal is thrown into, it immediately freezes. What fraction of water will freeze? The system is adiabatically isolated.
Answer» Solution :The HEAT of fusion LIBERATED in the process of freezing of water will be spent to heat the remaining water to `0^(@)C`. Let the total MASA of SUPERCOOLED water bem, the mass of ice formed my, the mass of remaining water `m_(2)=m-m_(1)` From the heat balance equation we have `m_(1)lambda=(m-m_(1))c Deltat,` whence `x=(m_(1))/(m)=(c Deltat)/(lambda+c Deltat)`

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Pure water can be supercooled down to -10^(@)C. If a small ice crystal is thrown into, it immediately freezes. What fraction of water will freeze? The system is adiabatically isolated.

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