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Pure water freezes at 273 K and 1 bar. The addition of 34.5 g of ethanol to 500 g of water changes the freezing point of the solution. Use the freezing point depression constant of water as 2 K kg mol^(-1).The figures shown below represent plots of vapour pressure (V.P.) versus temperature (T). [molecular weight of ethanol is 46 g mol^(-1) Among the following, the option representing change in the freezing point is |
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Answer»
`m=34.5/46xx1000/500` `DeltaT_(f)=34.5/46xx1000/500xx2=3` `T_(f)^(@)-T_(f)=273-T_(f)=3` `T_(f)=273-3=270K` |
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