Pure water freezes at 273 K and 1 bar. The addition of 34.5 g of ethanol to 500 g of water changes the freezing point of the solution. Use the freezing point depression constant of water at "2 K kg mol"^(-1). The figures shown below represent plots of vapour pressure (V.P.) versus temperature (T) [Molecular weight of ethanol is "46 g mol"^(-1)]. Among in the freezing point is

Pure water freezes at 273 K and 1 bar. The addition of 34.5 g of ethan

1.	Pure water freezes at 273 K and 1 bar. The addition of 34.5 g of ethanol to 500 g of water changes the freezing point of the solution. Use the freezing point depression constant of water at "2 K kg mol"^(-1). The figures shown below represent plots of vapour pressure (V.P.) versus temperature (T) [Molecular weight of ethanol is "46 g mol"^(-1)]. Among in the freezing point is
Answer» Solution :As T increases, V.P. increases. HENCE, option (c) and (d) are WRONG. `DeltaT_(F)=K_(f)xxm` `Delta_(f)^(@)-T_(f)=2xx(34.5//46)/(0.5)` `273-T_(f)=3 or T_(f)=270`. Hence, only option (a) is correct.