Pure water is saturated with pure solid AgCl, a silver electrode is placed in the solution and the potential is measured against normal calomel electrode at 25^(@)C. This experiment is then repeated with a saturated solution of Agl. If the difference in potential in the two cases is 0.177V. What is the ratio of solubility product (solubility) of AgCl and Agl at the temperature of the experiment?

Pure water is saturated with pure solid AgCl, a silver electrode is pl

1.	Pure water is saturated with pure solid AgCl, a silver electrode is placed in the solution and the potential is measured against normal calomel electrode at 25^(@)C. This experiment is then repeated with a saturated solution of Agl. If the difference in potential in the two cases is 0.177V. What is the ratio of solubility product (solubility) of AgCl and Agl at the temperature of the experiment?
Answer» `10^(3)` `10^(6)` `10^(2)` `10^(2)` SOLUTION :`AgtoAg^(+)+e^(-)` `E_(1)+E_("oxid")+E_("calomel")` `=E'-(0.0591)/(1)logK_(sp_(1))+E_("calomel")` `E_(2)=E'-(0.0591)/(1)logK_(sp_(2))+E_("calomel")` `E_(2)-E_(1)=0.177=0.0591log((K_(sp_(1)))/(K_(sp_(2))))` `(K_(sp_(1)))/(K_(sp_(2)))=10^(3)`