PVFor one gram molecular weight ofa gas- – InterviewSolution

1.

PVFor one gram molecular weight ofa gas-

Answer»

we know the relation as PV = nRT where n = no. of moles = (total mass)/(molecular weight ) = m/M

but here M = 1 gm , so n = m

so PV = mRT therefore PV/T = mR.

value in calories Pls

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