Saved Bookmarks
| 1. |
Pyrolustie on heating with KOH in the presence of air gives dark green compound (A).The solution of (A) on treatment with H_(2)SO_(4) gives a purple colouredcompound (B) which gives the following reactions : (i) Alkaline solution of B on reaction with KI changes it into compound (C ). (ii) The color of the compound (B) disappears on treatment with acidic soluiont of FeSO_(4). (iii) On reactionwith conc. H_(2)SO_(4) compound (B) gives another compound (D) which can decompose to produce compound (E ) along with oxygen gas. Identify compounds (A) to (E )and write balanced chemical equation involvedin eachcase. |
|
Answer» Solution :Chemical equation for the formation of A `:` ` underset("Pyrolusite")(2MnO_(2)) + 4KOH + O_(2) rarr underset("Potassium manganate ") underset((A))(2K_(2)MnO_(4)) +2H_(2)O` Chemical equation for theformation of B form A `:` `3K_(2)MnO_(4) + 2H_(2)SO_(4) rarr underset("POTASSIUMPERMANGANATE ")underset((B))(2KMnO_(4))+ MnO_(2) + 2K_(2)SO_(4) + 2H_(2)O` Chemical equationsof reaction of COMPOUND B `:` (i)` 2KMnO_(4) + H_(2)O+ KI rarr 2MnO_(2) + 2KOH + underset("Potassium iodate")underset((C ))(KIO_(3))` (ii) `2KMnO_(4)+ 10 FeSO_(4) + 8 H_(2)SO_(4) rarr K_(2)SO_(4) + 2MnSO_(4)+ 5Fe_(2)(SO_(4))_(3) + 8 H_(2)O` `2Mn_(2)O_(7) rarr underset((E )) (4 MnO_(2)) + 3O_(2)` |
|