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Q-10. Solve if possible ( x2 + 1 )2 - x2 = 0​

Answer»

Step-by-step explanation:

(<klux>X</klux> {}^{2} + 1)2 - x {}^{2} = 0 \\ 2x { }^{2} + 2 - x {}^{2} = 0 \\ x {}^{2} +2 = 0 \\ x (x + 2) = 0 \\

THEREFORE x can be 0 or - 2

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