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Q-12If a and B are the zeroes of the polynomial 6x2-x-2,find the value of (1/a + 1/B)​

Answer»

Answer:

-1/2

Explanation:

GIVEN POLYNOMIAL 6x^2-X-2=0

6x^2-4x+3x-2=0

2X(3x^2-2x) +1(3x^2-2) =0

(2x+1)(3x-2)=0

x= -1/2,2/3

Therefore a=-1/2 B=2/3

1/a+1/B = 1/-1/2 + 1/2/3

= -2+3/2

= -4+3/2

= -1/2



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