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Q-12If a and B are the zeroes of the polynomial 6x2-x-2,find the value of (1/a + 1/B) |
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Answer» Answer: -1/2 Explanation: GIVEN POLYNOMIAL 6x^2-X-2=0 6x^2-4x+3x-2=0 2X(3x^2-2x) +1(3x^2-2) =0 (2x+1)(3x-2)=0 x= -1/2,2/3 Therefore a=-1/2 B=2/3 1/a+1/B = 1/-1/2 + 1/2/3 = -2+3/2 = -4+3/2 = -1/2 |
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