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Q.1A wire of length 3.in the wire.0m has a percentage strain of 0.015% under a tensile force. Determine the extension |
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Answer» Here, original length, L = 3.0 mStrain =∆L/L = 0.015% = 0.015/100 ∆L = Strain x L or ∆L = extension = 0.015 / 100 x L= 0.015 x 3.0/100 = 0.00045m thanks |
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