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Q. 20, A solutionis 25% water, 25% ethanol and 50%acetic acid by mass. Calculate the mole fraction of each component

Answer»

Let the mass of solution is 100g then, mass of water = 25g mass of ethanol = 25g mass of acetic acid = 50g

Now, find number of moles of each components , Number of mole of water = mass of water/Molar mass of water = 25g/18g/mol [ ∵ molar mass of water = 18g/mol ] ≈ 1.4

Number of moles of ethanol = mass of ethanol/molar mass of ethanol= 25g/46g/mol [ ∵ molar mass of ethanol (C2H5OH) = 46g/mol = 0.54

Number of moles of acetic acid = mass of acetic acid/molar mass of acetic acid= 50g/60g/mol [∵ molar mass of acetic acid (CH3COOH) = 60g/mol]= 0.8 ∴ total number of moles = 1.4 + 0.54 + 0.8 = 2.74 Now, mole fraction of water = moles of water/total moles = 1.4/2.74 =0.51

similarly , mole fraction of ethanol = 0.54/2.74 = 0.197mole fraction of acetic acid = 0.8/2.74 = 0.291


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