Q. 7. In the fig., ABC is a right-angled triangle, ZB = 90°, AB = 28 cm and BC = 21 cm. With AC as diameter,a semi-circle is drawn and with BC as radius aquarter circle is drawn. Find the area of the shadedregion.

Q. 7. In the fig., ABC is a right-angled triangle, ZB = 90°, AB = 2

1.	Q. 7. In the fig., ABC is a right-angled triangle, ZB = 90°, AB = 28 cm and BC = 21 cm. With AC as diameter,a semi-circle is drawn and with BC as radius aquarter circle is drawn. Find the area of the shadedregion.
Answer» hope its helps u............hit brainlestStep-by-step explanation:The area of the shaded REGION = Area of Semi-circle + Area of TRIANGLE ABC - Area of quarter circle Area of triangle = 1/2 x 21 x 28 = 294 cm² To FIND area of semi-circle; AC² = 28² + 21² = 1225 AC = 35 Radius of semi-circle = 35/2 = 17.5 Area = 1/2 x 3.14 x (17.5)² = 480.8 cm² Area of quarter circle = 1/4 x 3.14 x 21²= 346.2 cm² Area of shaded region = 294 + 480.8 - 346.2 = 428.75cm²

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Q. 7. In the fig., ABC is a right-angled triangle, ZB = 90°, AB = 28 cm and BC = 21 cm. With AC as diameter,a semi-circle is drawn and with BC as radius aquarter circle is drawn. Find the area of the shadedregion.​

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Q. 7. In the fig., ABC is a right-angled triangle, ZB = 90°, AB = 28 cm and BC = 21 cm. With AC as diameter,a semi-circle is drawn and with BC as radius aquarter circle is drawn. Find the area of the shadedregion.