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Q. A quadrilateral ABCD is drawn to circumscribe a circle. If AB = 5 cm and CD = 9 cm , BC = 8 cm , then the AD is what ?? |
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Answer» ABCD CIRCUMSCRIBES a circle.Tangents from an external POINT to a circle are equal..•. AP=AS(tangents FRM A,P is PT of contact)-------1BP=BQ(tangents frm B,Q is pt of contact)-------2CR=CQ(tangents frm C,R is pt of contact--------3DR=DS(tangents frm D,S is pt of contact)-------4From eq. 1,2,3&4AB+CD=AD+BC=5+9=AD+8=14-8=AD=AD=6cm |
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