1.

Q. Calculate the area of the region enclosed between the circles: x2 + y2 = 16 and (x + 4)2 + y2 = 16...Sραɱɱҽɾ ʂƚαყ αɯαყ....​

Answer»

Here x

2

+y

2

=16

∴y

2

=16−x

2

y=

4

2

−x

2

AREA =

0

∫

π/2

4 2 −x 2 dx

=[ 2]

x( 4 2 −x 2 ) + 24 2

SIN −1 ( 4π )] 0π/2

=( 24(0) + 216 sin −1 (1))−(0+ 216 sin −1 (0))

=0+8( 2π )−0

∴ REQUIRED area =4π


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