Q) In fig, if AB ∥ MN, ∠AQM = 42° ∠QBP = 130°, find the value

1.	Q) In fig, if AB ∥ MN, ∠AQM = 42° ∠QBP = 130°, find the value of x, y.
Answer» Answer: X = 88° and Y = 42° Step-by-step explanation: GIVEN that AB\|\| MN. Therefore, ∠BQM = ∠QBP ( ALTERNATE angles are EQUAL) => ∠AQM + x = 130° => 42° + x = 130° => x = 130° - 42° = 88° ∠AQM = y (alternate angles) => y = 42°

Q) In fig, if AB ∥ MN, ∠AQM = 42° ∠QBP = 130°, find the value of x, y.

Answer»

Answer:

X = 88° and Y = 42°

Step-by-step explanation:

GIVEN that AB|| MN.

Therefore, ∠BQM = ∠QBP ( ALTERNATE angles are EQUAL)

=> ∠AQM + x = 130°

=> 42° + x = 130°

=> x = 130° - 42° = 88°

∠AQM = y (alternate angles)

=> y = 42°