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                                    Q. Let `P={theta:sin theta-cos theta=sqrt2 cos theta}` and `Q={theta:sin theta+cos theta=sqrt2 sin theta}` be two sets. thenA. `P sub Q and Q-P ne phi`B. `Q cancel(sub) P`C. `P cancel(sub)Q`D. `P = Q` | 
                            
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Answer» Correct Answer - D `P = {theta: sin theta -costheta = sqrt(2) cos theta}` `rArr cos theta (sqrt(2)+1) = sin theta` ` rArr tan theta = sqrt(2)+1` `rArr Q = { theta : sin theta + cos theta} = sqrt(2) sin theta` `rArr sin theta (sqrt(2) -1) = cos theta` `rArr tan theta =(1)/(sqrt(2-1)) xx (sqrt(2)+1)/(sqrt(2)+1) = (sqrt(2)+1)` `therefore P =Q`  | 
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