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Q. y=-1/√5 ,y=2/√5 are zeroes of p(y) = (1-5y²) |
Answer» <html><body><p> <a href="https://interviewquestions.tuteehub.com/tag/quadratic-610697" style="font-weight:bold;" target="_blank" title="Click to know more about QUADRATIC">QUADRATIC</a> <a href="https://interviewquestions.tuteehub.com/tag/polynomial-1158688" style="font-weight:bold;" target="_blank" title="Click to know more about POLYNOMIAL">POLYNOMIAL</a> is y2+235y−5.</p><p>The <a href="https://interviewquestions.tuteehub.com/tag/zeros-751194" style="font-weight:bold;" target="_blank" title="Click to know more about ZEROS">ZEROS</a> of the polynomial are:</p><p> y2+235y−5=0</p><p>⟹ y2+25y−25y−5=0</p><p>⟹ y(y+25)−25(y+25)=0</p><p>⟹ (y+25)(y−25)=0</p><p>⟹ y−25 and y=25=0</p><p>The zeros are −25 and <a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a></p><p></p><p></p><p></p></body></html> | |