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Q12 In the year 2012, the average age of a family of 3 members was 18 years. Two children having been born (with age difference of 4 years), the present sum of age of the family is 90 years. The present age of the youngest child is :(a) 1(b) 2.(C) 3(d) 4​

Answer»

the AVERAGE AGE of a FAMILY of 3 members was 18 yrs The sum of it is = 18*3 =54present sum of age of the family is 90 years 54 + X + x-4 = 90 2X - 4 =90-542x = 36+4 = 40x = 20x-4 = 16



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