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Q15 If a+b+c = 6 and ab+bc+ca = 11, find a ^2+b^2+c^2 |
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Answer» 14Step-by-step explanation:Given :a + B + C = 6Squaring on both SIDES=> ( a + b + c )² = 6²Using algebraic identity ( a + b + c) ² = a² + b² + c² + 2( ab + bc + ca) => a² + b² + c² + 2( ab + bc + ca ) = 36=> a² + b² + c² + 2( 11 ) = 36=> a² + b² + c² + 22 = 36 => a² + b² + c² = 36 - 22=> a² + b² + c² = 14Therefore the value of a² + b² + c² is 14 |
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