Q17. find the length of the hypotenuse of a right isosceles triangle w

1.	Q17. find the length of the hypotenuse of a right isosceles triangle whose area is 961 sq. cm.
Answer» Answer: Length of hypotenuse is x Area is $961^{2} cm$ Area of triangle= $\frac{1}{2}$ ×b×h so, 961= $\frac{1}{2}$ ×b×b (as isosceles triangle, the TWO SIDES EXCEPT the hypotenuse are same) 961×2= $x^{b}$ 1922= $b^{2}$ $\sqrt{1922}$ =b 43=b (approx.) so, using PYTHAGORAS theorem we can find hypotenuse $43^{2}$ + $43^{2}$ = $x^{2}$ 3698= $x^{2}$ $\sqrt{3698\\}$ = $x^{2}$ 60=x (approx.)