Q19. The percentage increase in the surface area of a cube when each side is increased to 3/2 times the original length is *0 2253250425O 125Q20. *The radius and height of a cone are each increased by 20%, then the volume of the cone is increased by

Q19. The percentage increase in the surface area of a cube when each s

1.	Q19. The percentage increase in the surface area of a cube when each side is increased to 3/2 times the original length is 0 2253250425O 125Q20. The radius and height of a cone are each increased by 20%, then the volume of the cone is increased by
Answer» e of the CUBE be X. Then its total surface AREA =6x2.If each side is increased to 23xTotal surface area =6×23x×23x=227x2∴ INCREASE =227x2−6x2=215x2∴ % increase =215x2×6x2100=125