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Q2 If the length of the diagonals of the rhombus are 30 cm and 40 cm. Then thesum of squares of its sides is25 sq cm625 sq cm2500 sq cm1250 sq cm​

Answer»

Answer:

25 sq cm

Step-by-step explanation:

Let ABCD be a rhombus and AC and BD be the diagonals of ABCD. So, AC = 30 cm and BD = 40 cm

We know that diagonals of a rhombus bisect each other at right angle. (PERPENDICULAR to each other) So, AO = OC = 15 cm and BO = OD = 20 cm In ∆AOB, by Pythagoras theorem,

AB2 = AO2 + BO2 = 152 + 202 = 225 + 400 = 625 ⇒ AB = √625 = 25 cm Since, the sides of rhombus are all equal. Therefore, AB = BC = CD = AD = 25 cm

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