Q2.Write the numbers given in the following place value table in decim

1.	Q2.Write the numbers given in the following place value table in decimal form.Hundreds Tens Ones Tenths Hundredths Thousandths(100) (10) (1)111010010000520032036102.5.0030.2(a)(6)(c)(d)(e)90112.142210
Answer» ANSWER: This implies that x2+2ax=4x−4a−13 or x2+2ax−4x+4a+13=0 or x2+(2a−4)x+(4a+13)=0 Since the equation has just one solution INSTEAD of the usual two DISTINCT solutions, then the two solutions must be same i.e. discriminant = 0. Hence we get that (2a−4)2=4⋅1⋅(4a+13) or 4a2−16a+16=16a+52 or 4a2−32a−36=0 or a2−8a−9=0 or (a−9)(a+1)=0 So the VALUES of a are −1 and 9.

Q2.Write the numbers given in the following place value table in decimal form.Hundreds Tens Ones Tenths Hundredths Thousandths(100) (10) (1)111010010000520032036102.5.0030.2(a)(6)(c)(d)(e)90112.142210

Answer»

This implies that

x2+2ax=4x−4a−13

x2+2ax−4x+4a+13=0

x2+(2a−4)x+(4a+13)=0

Since the equation has just one solution INSTEAD of the usual two DISTINCT solutions, then the two solutions must be same i.e. discriminant = 0.

Hence we get that

(2a−4)2=4⋅1⋅(4a+13)

4a2−16a+16=16a+52

4a2−32a−36=0

a2−8a−9=0

(a−9)(a+1)=0

So the VALUES of a are −1 and 9.