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Q9. The expected value of the number of heads when two coins are tossed is * O 1 O 1/2 O 3/4 O 1/8​

Answer»

<P>Answer:

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Step-by-step explanation:

PROBABILITY of getting head p= 2/1

Probability of not getting head q=1−

2/1

= 2/1

Number of coins =3

Expected value E(x)=np

=3×2/1

=1.5



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