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Quantity B: 30001). Quantity A > Quantity B2). Quantity A < Quantity B3). Quantity A ≥ Quantity B4). Quantity A ≤ Quantity B |
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Answer» Quantity A: Four gadgets can be chosen such that there is at LEAST one gadget of each type, if two gadgets of one of the type is chosen and one gadget of remaining two types is chosen. ∴ NUMBER of ways in which this can be DONE = 7C2 × 6C1 × 8C1 + 7C1 × 6C2 × 8C1+ 7C1 × 6C1 × 8C2 = 3024 Quantity B: 3000 ∴ Quantity A < Quantity B |
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