Quantity B: 4381). Quantity A > Quantity B2). Quantity A < Quantity B3

1.	Quantity B: 4381). Quantity A > Quantity B2). Quantity A < Quantity B3). Quantity A ≥ Quantity B4). Quantity A ≤ Quantity B
Answer» Quantity A: ORIENT First we will fix the first LETTER: E, I & N then O will come; No. of words possible with E as the first letter = 5! = 120 No. of words possible with I as the first letter = 5! = 120 No. of words possible with N as the first letter = 5! = 120 Now, we will fix first two letters: OE, OI and ON, then OR will come; No. of words possible with OE as first two letters = 4! = 24 No. of words possible with OI as first two letters = 4! = 24 No. of words possible with ON as first two letters = 4! = 24 Now, we will fix first THREE letters: ORE, then ORI will come; No. of words possible with ORE as first three letters = 3! = 6 Then the word ‘ORIENT’ will come (It will be the first word starting with ORI) ∴ RANK of ‘ORIENT’ in the dictionary = 360 + 72 + 6 + 1 = 439 Quantity B: 438 ∴ Quantity A > Quantity B

Quantity B: 4381). Quantity A > Quantity B2). Quantity A < Quantity B3). Quantity A ≥ Quantity B4). Quantity A ≤ Quantity B

Answer»

Quantity A:

ORIENT

First we will fix the first LETTER: E, I & N then O will come;

No. of words possible with E as the first letter = 5! = 120

No. of words possible with I as the first letter = 5! = 120

No. of words possible with N as the first letter = 5! = 120

Now, we will fix first two letters: OE, OI and ON, then OR will come;

No. of words possible with OE as first two letters = 4! = 24

No. of words possible with OI as first two letters = 4! = 24

No. of words possible with ON as first two letters = 4! = 24

Now, we will fix first THREE letters: ORE, then ORI will come;

No. of words possible with ORE as first three letters = 3! = 6

Then the word ‘ORIENT’ will come (It will be the first word starting with ORI)

∴ RANK of ‘ORIENT’ in the dictionary = 360 + 72 + 6 + 1 = 439

Quantity B: 438

∴ Quantity A > Quantity B