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Ques. 1 (MMCO)The position of a particle varies with time as ř = a sin 2tî + a cos 2tî + btê. Then theAtrajectory of particle as seen by an observer moving with a velocity bê is a circle.trajectory of the particle w.r.t. ground observer is a circleBCangle between velocity and acceleration is 5Dangle between velocity and acceleration is constant |
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Answer» Step-by-step EXPLANATION: Position of a particle x(t)=3T −4t +2 m Differentiating w.r.t time we get v(t)= dt dx(t)
=9t 2 −8t m/s Thus ACCELERATION of the particle a(t)= dt dv(t)
=18t−8 m/s 2
⟹ a ∣ ∣ ∣ ∣ ∣
t=2s
=18×2−8=28 m/s 2 |
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