Question 1.Given: In AABC, 2B=90°.If 15 cot A=8, Find sin Aand sec A.

1.	Question 1.Given: In AABC, 2B=90°.If 15 cot A=8, Find sin Aand sec A.
Answer» 5cotA=8cotA= 15/8 => tanA= 8/15 -------(tanA= cotA=1)We know that,tanθ= adjacentSide,oppositeSideConsider the attached figure, triangleABCFrom PYTHAGORAS theorem,2AC =2AB +2BC 2AC =8(2)+15(2) 2AC=64+225=289AC=17cosA= HYPOTENUSE adjacentSide = AC/AB = 17/8 SECA= cosA 1 = 17/8= 18/17sinA= Hypotenuse oppositeSide = AC/BC = 17/15 solution

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Question 1.Given: In AABC, 2B=90°.If 15 cot A=8, Find sin Aand sec A.​

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Question 1.Given: In AABC, 2B=90°.If 15 cot A=8, Find sin Aand sec A.