Question 31 The value of (3x3+9x2+27x)÷3x is a) x2+9+27x b) 3x3+3x2 – InterviewSolution

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1.	Question 31 The value of (3x3+9x2+27x)÷3x is a) x2+9+27x b) 3x3+3x2+27x c) 3x3+9x2+9 d) x2+3x+9
Answer» Question 31 The value of $(3 x^{3} + 9 x^{2} + 27 x) \div 3 x$ is a) $x^{2} + 9 + 27 x$ b) $3 x^{3} + 3 x^{2} + 27 x$ c) $3 x^{3} + 9 x^{2} + 9$ d) $x^{2} + 3 x + 9$

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