Question 6The following table gives the distribution of students of two sections according to the marks obtained by them:Section ASection BMarksFrequencyMarksFrequency0−1030−10510−20910−201920−301720−301530−401230−401040−50940−501Represent the marks of the students of both the sections on the same graph by two frequency polygons. From the two polygons compare the performance of the two sections.

Question 6The following table gives the distribution of students of tw

1.	Question 6The following table gives the distribution of students of two sections according to the marks obtained by them:Section ASection BMarksFrequencyMarksFrequency0−1030−10510−20910−201920−301720−301530−401230−401040−50940−501Represent the marks of the students of both the sections on the same graph by two frequency polygons. From the two polygons compare the performance of the two sections.
Answer» Question 6 The following table gives the distribution of students of two sections according to the marks obtained by them: $\begin{matrix} Section A & Section B Marks & Frequency & Marks & Frequency 0 - 10 & 3 & 0 - 10 & 5 10 - 20 & 9 & 10 - 20 & 19 20 - 30 & 17 & 20 - 30 & 15 30 - 40 & 12 & 30 - 40 & 10 40 - 50 & 9 & 40 - 50 & 1 \end{matrix}$ Represent the marks of the students of both the sections on the same graph by two frequency polygons. From the two polygons compare the performance of the two sections.