Question 7tan θ+tan(90∘−θ)=sec θ.sec(90∘−θ)

1.	Question 7tan θ+tan(90∘−θ)=sec θ.sec(90∘−θ)
Answer» Question 7 $t a n θ + t a n (90^{\circ} - θ) = s e c θ . s e c (90^{\circ} - θ)$

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