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QUESTION: A factory kept increasing its output by the same percentage every year . Find the percentage if it is known that the output is doubled in the last two years. |
Answer» <html><body><h3>||✰✪QUESTION✰✪||</h3><p>QUESTION: A factory kept increasing its output by the same percentage every year . <a href="https://interviewquestions.tuteehub.com/tag/find-11616" style="font-weight:bold;" target="_blank" title="Click to know more about FIND">FIND</a> the percentage if it is known that the output is doubled in the last two <a href="https://interviewquestions.tuteehub.com/tag/years-1464846" style="font-weight:bold;" target="_blank" title="Click to know more about YEARS">YEARS</a>.</p><h3>||✪✪ GIVEN ✪✪||</h3><ul><li>output <a href="https://interviewquestions.tuteehub.com/tag/increase-1040383" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASE">INCREASE</a> same every year.</li><li>In last two years output is doubled .. </li></ul><h3>|| ✰✰ ANSWER ✰✰ ||</h3><p></p><p>Let The initital Output was X . (Before Two year). </p><p></p><p>And, Let Each Year it increases by Y% .. </p><p></p><p>It is given That , now, In last two years output is doubled .. So, Output become = 2 * X = 2X . </p><p></p><h3>A/q, </h3><p>→ X[ 1 + (y/100)]² = 2X</p><p><strong>Dividing both sides by X,</strong></p><p>→ [ 1 + (y/100)]² = 2</p><p><strong>Square - Root Both sides now, </strong></p><p>→ [ 1 + (y/100)] = √2</p><p><strong>Putting <a href="https://interviewquestions.tuteehub.com/tag/value-1442530" style="font-weight:bold;" target="_blank" title="Click to know more about VALUE">VALUE</a> of √2 as <u>1.4142</u> now ,</strong></p><p>→ [ 1 + (y/100)] = 1.4142</p><p>→ (y/100) = 1.4142 - 1 </p><p>→ (y/100) = 0.4142</p><p>→ y = 100 * 0.4142 </p><p>→ y = 41.42% . </p><p></p><h3><strong><u><a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a></u></strong>, </h3><p>The Required % which increase Every year is <img align="absmiddle" alt="\sf\fbox{41.42}" class="latex-formula" id="TexFormula1" src="https://tex.z-dn.net/?f=%5Csf%5Cfbox%7B41.42%7D" title="\sf\fbox{41.42}"/>%</p></body></html> | |