Question.. don't spam ❌

1.	Question.. don't spam ❌
Answer» ${\huge{\underline{\underline{\bf{Question :-}}}}}$ FIND x $\large \rm \: \dfrac{1 - \frac{1 + \frac{1 - x}{3} }{3} }{4} = 1$ ${\huge{\underline{\underline{\bf{Answer\checkmark}}}}}$ Take LCM $\rm \mapsto \large \: \frac{1 - \frac{ \frac{3 + 1 - x}{3} }{3} }{4} = 1 \\$ $\large\mapsto \rm \frac{1 - \frac{4 - x}{9} }{4} = 1 \\$ $\large \rm \mapsto \: \frac{9 - (4 - x)}{9} = 1 \times 4$ $\mapsto \rm \: 9 - 4 + x = 4 \times 9$ $\mapsto \rm \: 5 + x = 36$ $\mapsto \rm \: x = 36 - 5$ $\large\mapsto \boxed{ \rm \: x = <klux>31</klux>}$ So , For x = 31 , this equation is valid .. ★ Verification : PUT x = 31 in LHS $\rm \large \frac{1 - \frac{1 + \frac{1 - 31}{3} }{3} }{4} \\$ $\large\implies \rm \frac{1 - \frac{1 + \frac{ - \cancel{30}}{ \cancel3} }{3} }{4} \\$ $\large \implies \rm \: \frac{1 - \frac{1 - 10}{3} }{4} \\$ $\large \implies \rm \: \frac{1 - \cancel{ \frac{ - 9}{3} }}{4} \\$ $\implies \rm \: \frac{1 - (- 3)}{4} \\$ $\implies \rm \: \frac{1 + 3}{4} \\$ $\implies \cancel{ \frac{4}{4}} \\$ $\implies \: 1$ So , LHS = RHS , hence verified ..

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