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Questions 55 and 56 are based on following paragraph : In Young's double slit experiment, the distance between two slits is 1 mm. And distance between slits and screen is 1.0 meter. The wavelength of light used is 6000 Å. Two waves are equal. 55. The fringe width is

Answer»

`0.3 mm`
`0.6 mm`
`0.8 mm`
`2 mm`

Solution :FRINGE width `BETA = (lambdaD)/(2d) = (1 xx 6000 xx 10^(-10))/(10^(-3)) = 0.6 mm`


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