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Questions 59 and 60 are based on following paragraph : A beam of light consisting of two wavelengths 6500 Å and 5200 Å is used to get interference fringes in Young's double slit experiment with slit distance 2 mm and screen distance 120 cm. 59.The distance of 3rd fringe on screen from central maxima for wavelength 6500 Å is

Answer»

`2.02 mm`
`1.17 mm`
`0.95 mm`
`0.67 mm`

Solution :For bright fringes, `x_(n) = (n lambdaD)/(d)`
`therefore x_(3) = (3 XX 6500 xx 10^(-10) xx 120)/(0.2) = 0.117cm`
` = 1.17 mm`.


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