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Questions numbers 149-150 are based on the following paragraph : A nucleus of mass M + Deltam is at rest and decays into two daughter nuclei of equal mass M/2 each. Spped of light is c. 149. The speed of daughter nuclei is :

Answer»

`csqrt((DELTAM)/(M + Deltam))`
`C = (Deltam)/(M + Deltam)`
`c = sqrt((2 DeltaM)/(M))`
`csqrt((Deltam)/(M))`

Solution :MASS defect = `Deltam`
Energy released = `Deltamc^(2)`
or `2KE = DeltaMC^(2)`
` 2 xx(1)/(2)((M)/(2))V^(2) = Deltamc^(2)`
`THEREFORE V = sqrt((2Deltam)/(M))c^(2) = csqrt((2Deltam)/(M))`


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