1.

R is a relation from {11, 12, 13} to {8, 10, 12} defined by y = x− 3. Then, R−1 is A. {(8, 11), (10, 13)} B. {(11, 8), (13, 10)} C. {(10, 13), (8, 11), (12, 10)} D. none of these.

Answer»

Option : (A)

Since, 

y = x – 3;

Therefore, 

for x = 11, y = 8. 

For x = 12, y = 9.

[But the value y = 9 does not exist in the given set.] 

For x = 13, y =10. 

So, we have 

R = {(11, 8), (13, 10)} 

Now, 

R−1 = {(8, 11), (10, 13)}.



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