`R` is the radius of the earth and `omega` is its angular velocity and `g_(p)` is the value of `g` at the poles. The effective value of `g` at the latitude `lambda=60^(@)` will be equal toA. `g_(p)-1/4 Romega^(2)`B. `g_(p)-3/4 R omega^(2)`C. `g_(p)-Romega^(2)`D. `g_(p)+1/4 Romega^(2)`

`R` is the radius of the earth and `omega` is its angular velocity and

1.	`R` is the radius of the earth and `omega` is its angular velocity and `g_(p)` is the value of `g` at the poles. The effective value of `g` at the latitude `lambda=60^(@)` will be equal toA. `g_(p)-1/4 Romega^(2)`B. `g_(p)-3/4 R omega^(2)`C. `g_(p)-Romega^(2)`D. `g_(p)+1/4 Romega^(2)`
Answer» Correct Answer - A

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`R` is the radius of the earth and `omega` is its angular velocity and `g_(p)` is the value of `g` at the poles. The effective value of `g` at the latitude `lambda=60^(@)` will be equal toA. `g_(p)-1/4 Romega^(2)`B. `g_(p)-3/4 R omega^(2)`C. `g_(p)-Romega^(2)`D. `g_(p)+1/4 Romega^(2)`

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